0=-16x^2+300x+20

Solution for 0=-16x^2+300x+20 equation:

0=-16x^2+300x+20

We move all terms to the left:

0-(-16x^2+300x+20)=0

We add all the numbers together, and all the variables

-(-16x^2+300x+20)=0

We get rid of parentheses

16x^2-300x-20=0

a = 16; b = -300; c = -20;
Δ = b2-4ac
Δ = -3002-4·16·(-20)
Δ = 91280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{91280}=\sqrt{16*5705}=\sqrt{16}*\sqrt{5705}=4\sqrt{5705}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-4\sqrt{5705}}{2*16}=\frac{300-4\sqrt{5705}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+4\sqrt{5705}}{2*16}=\frac{300+4\sqrt{5705}}{32}
$